< Summary

Information
Class: LeetCode.Algorithms.RotateArray.RotateArrayCycleReplacement
Assembly: LeetCode
File(s): D:\a\LeetCode-CS\LeetCode-CS\source\LeetCode\Algorithms\RotateArray\RotateArrayCycleReplacement.cs
Line coverage
100%
Covered lines: 19
Uncovered lines: 0
Coverable lines: 19
Total lines: 53
Line coverage: 100%
Branch coverage
100%
Covered branches: 6
Total branches: 6
Branch coverage: 100%
Method coverage

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Metrics

MethodBranch coverage Crap Score Cyclomatic complexity Line coverage
Rotate(...)100%66100%

File(s)

D:\a\LeetCode-CS\LeetCode-CS\source\LeetCode\Algorithms\RotateArray\RotateArrayCycleReplacement.cs

#LineLine coverage
 1// --------------------------------------------------------------------------------
 2// Copyright (C) 2026 Eugene Eremeev (also known as Yevhenii Yeriemeieiv).
 3// All Rights Reserved.
 4// --------------------------------------------------------------------------------
 5// This software is the confidential and proprietary information of Eugene Eremeev
 6// (also known as Yevhenii Yeriemeieiv) ("Confidential Information"). You shall not
 7// disclose such Confidential Information and shall use it only in accordance with
 8// the terms of the license agreement you entered into with Eugene Eremeev (also
 9// known as Yevhenii Yeriemeieiv).
 10// --------------------------------------------------------------------------------
 11
 12namespace LeetCode.Algorithms.RotateArray;
 13
 14/// <inheritdoc />
 15public sealed class RotateArrayCycleReplacement : IRotateArray
 16{
 17    /// <summary>
 18    ///     Time complexity - O(n)
 19    ///     Space complexity - O(1)
 20    /// </summary>
 21    /// <param name="nums"></param>
 22    /// <param name="k"></param>
 23    public void Rotate(int[] nums, int k)
 524    {
 525        var n = nums.Length;
 26
 527        k %= n;
 28
 529        if (k == 0)
 330        {
 331            return;
 32        }
 33
 234        var count = 0;
 35
 1036        for (var index = 0; count < n; index++)
 337        {
 338            var currentIndex = index;
 339            var previousValue = nums[index];
 40
 41            do
 1142            {
 1143                var nextIndex = (currentIndex + k) % n;
 44
 1145                (nums[nextIndex], previousValue) = (previousValue, nums[nextIndex]);
 46
 1147                currentIndex = nextIndex;
 48
 1149                count++;
 2250            } while (currentIndex != index);
 351        }
 552    }
 53}