| | 1 | | // -------------------------------------------------------------------------------- |
| | 2 | | // Copyright (C) 2025 Eugene Eremeev (also known as Yevhenii Yeriemeieiv). |
| | 3 | | // All Rights Reserved. |
| | 4 | | // -------------------------------------------------------------------------------- |
| | 5 | | // This software is the confidential and proprietary information of Eugene Eremeev |
| | 6 | | // (also known as Yevhenii Yeriemeieiv) ("Confidential Information"). You shall not |
| | 7 | | // disclose such Confidential Information and shall use it only in accordance with |
| | 8 | | // the terms of the license agreement you entered into with Eugene Eremeev (also |
| | 9 | | // known as Yevhenii Yeriemeieiv). |
| | 10 | | // -------------------------------------------------------------------------------- |
| | 11 | |
|
| | 12 | | using LeetCode.Core.Models; |
| | 13 | |
|
| | 14 | | namespace LeetCode.Algorithms.BinaryTreeInorderTraversal; |
| | 15 | |
|
| | 16 | | /// <inheritdoc /> |
| | 17 | | public class BinaryTreeInorderTraversalStack : IBinaryTreeInorderTraversal |
| | 18 | | { |
| | 19 | | /// <summary> |
| | 20 | | /// Time complexity - O(n) |
| | 21 | | /// Space complexity - O(n) |
| | 22 | | /// </summary> |
| | 23 | | /// <param name="treeNode"></param> |
| | 24 | | /// <returns></returns> |
| | 25 | | public IList<int> InorderTraversal(TreeNode? treeNode) |
| 3 | 26 | | { |
| 3 | 27 | | if (treeNode == null) |
| 1 | 28 | | { |
| 1 | 29 | | return new List<int> { 0 }; |
| | 30 | | } |
| | 31 | |
|
| 2 | 32 | | var result = new List<int>(); |
| 2 | 33 | | var stack = new Stack<TreeNode>(); |
| 2 | 34 | | var current = treeNode; |
| | 35 | |
|
| 6 | 36 | | while (current != null || stack.Count > 0) |
| 4 | 37 | | { |
| 8 | 38 | | while (current != null) |
| 4 | 39 | | { |
| 4 | 40 | | stack.Push(current); |
| 4 | 41 | | current = current.left; |
| 4 | 42 | | } |
| | 43 | |
|
| 4 | 44 | | current = stack.Pop(); |
| 4 | 45 | | result.Add(current.val); |
| | 46 | |
|
| 4 | 47 | | current = current.right; |
| 4 | 48 | | } |
| | 49 | |
|
| 2 | 50 | | return result; |
| 3 | 51 | | } |
| | 52 | | } |